Riddles! Give it a try....

[Paula Gottsch (Willson)]

Shame, maybe he just takes longer translating all the info from English in German.

  :emot19:

(Georg jr here's a peek at my heart, don't blink or you will miss it)

We still love you, so don't go jump off a bridge now ok!

e154

[georg ruf jr.]

Were you picking on me behind my back again?

[georg ruf jr.]

Number 7
Santa had a hard time getting all the presents to everybody in time this year. So he's wondering how to improve next time. His tempo depends on the amount of reindeers he uses for the sled.
He always harneses them in a certain patten. there are always 2 reindeers in front of another.
Part 1.) He had 4 rows lastyear. How many reindeer?
Part 2.) He is planing 10 rows this year. How many reindeer?

Hint: The answer is neither Paula nor Diana.
            There are 2 answers to this one.

[barb (Fry)]

1.  16
2. 100 (this would be turbo)!!

[georg ruf jr.]

Sorry Barb. It would have been turbo, but it isn't.
Remember. There's always something tricky about these riddles.
Try again.

[barb (Fry)]

1. 15
2. 432 - wow

[georg ruf jr.]

Okay Barb. Part one is done. Now you know how it works. Make a mathatical formula out of it, and you'll no the answer to any amount of rows.
Part 1.) 15 reindeers
Try part two again...

[barb (Fry)]

silly me -
part 2 883

[georgswa (Georg Ruf) (RIP)]

@@  @@  @@  @@

@@  @@  @@  @@

@@  @@  @@  @@

@@  @@  @@  @@     = 15 ????????????????????????????????????????????????????????????????????


I see here 4 rows, there are always 2 reindeers in front of another

You must explain son where have you lost the one ????? Trying to be funny ????? 

Ambigious questions result in ambigious answers

[Diana Rudd (Boehme)]

If you ALWAYS have to have 2 Reindeers INFRONT of another it would go on for ever or form a circle.

                                                                OR

@ @
  @   (another)
@ @
  @   (another)
@ @
  @   (another)
@ @
  @   (another)
@ @
  @   (another)    =  15   last yearwould be 6

[georgswa (Georg Ruf) (RIP)]

If you ALWAYS have to have 2 Reindeers INFRONT of another it would go on for ever or form a circle.

                                                                OR

@ @
  @   (another)
@ @
  @   (another)
@ @
  @   (another)
@ @
  @   (another)
@ @
  @   (another)    =  15   last yearwould be 6

There you are.....i cant see the 4 rows, thats what i ment with ambiguity

Or name this way, if you ask stupid questions, dont expect clever answers 

[georg ruf jr.]

Ask Barb. She's understood.
 

Okay oldman. Here we go.


You take a reindeer. Put two in front of him. Makes three. Then you put two in front of the front two. Makes 7. Got it? All you have to do is count from now on. Easy enough? Hihihihi. I think that even Paula will cope now.

[barb (Fry)]

eg;

                @@@@  @@@@
                  @@       @@
                   @          @   
                         @

[georg ruf jr.]

Very good Barb. Show the rest how its done.    e154

[georg ruf jr.]

silly me -
part 2 883

Part 2.) is still missing.